Solution:
SOLUTION
CO2(g) + C(s) ? 2CO(g)
If x is the mole fraction of CO at equilibrium,
then PCO = x.p = x × 4
and, PCO2 = (1 - x).P = (1 - x) × 4
Then, Kp = 9 = $$\cfrac{P_{CO}^{2}}{{{P}_{C{{O}_{2}}}}}\,=\,\cfrac{{{(4x)}^{2}}}{4(1-x)}$$ or x = 0.75
75%