Solution:
Solution
Given mass=220 mg=0.220 g
Molar mass of $$CO_{ 2 }$$=44 g
No. of moles=$$\dfrac { 0.220 }{ 44 } =0.005$$
No. of moles=$$\dfrac { Total\quad number\quad of\quad molecules }{ Avogadro\quad number } \\ $$
No. of molecules=$$0.005\times 6.022\times { 10 }^{ 23 }$$=0.03$$\times { 10 }^{ 23 }$$
Remaining Number of molecules=$$0.03\times { 10 }^{ 23 }$$-$$66\times { 10 }^{ 20 }$$
=$$24\times { 10 }^{ 20 }$$
No. of moles remaining =$$\dfrac { 24\times { 10 }^{ 20 } }{ 6.022\times \times { 10 }^{ 23 } } =0.0039=4\times { 10 }^{ -3 }$$
