Solution:
Solution
Strength of the solution $$=34 $$ g/L.
1 L (or 1000 mL) of the solution contains 34 g of $$H_2O_2$$
200 mL of the solution contains $$\dfrac{34}{1000} \times 200= 6.8 $$ g of $$H_2O_2$$
$$2H_2O_2\rightarrow2H_2O+O_2$$
2 moles of $$H_2O_2$$ gives 1 mole of $$O_2$$
68g of $$H_2O_2$$ gives $$ 32$$ g of $$O_2$$
6.8g of $$H_2O_2$$ gives $$\dfrac{32}{68} \times 6.8= 3.2$$ g of $$O_2$$
