Solution

On moving down the group of alkaline earth metals, the solubility of metal sulphates decreases. Also, the ionic size increases and hydration energy of metal ion decreases. Hence, magnesium sulphate(MgSO₄) has lowest solubility. 

SOLUTION

Aldhyde behaves as a functional group and numbering starts from terminal functional group.

2−Hydroxy−4−Oxopentanal

Solution

Ambidentate ligand has two or more donor atoms, but during complex formation, only one donor atom is attached to central metal. SCN− ion has donor atoms N and S. It links to metal as either M−SCN or M−NCS. NO₂⁻ group has donor atoms N and O. It links to metal as either M−ONO or M−NO2.

Solution

The Tyndall effect is light scattering by particles in a colloid or in a very fine suspension.
Coagulation is a chemical process that involves neutralization of charge whereas flocculation is a physical process and does not involve neutralization of charge.
Electrophoresisstrong - > is the motion of dispersed particles relative to a fluid under the influence of a spatially uniform electric field. Electrophoresis of positively charged particles is sometimes called cataphoresis, while electrophoresis of negatively charged particles is sometimes called anaphoresis.
Electro-osmosisstrong - > refers to the movement of liquid in a porous material due to an applied electric field

Solution

Solution

The rate of diffusion  is the ratio of number of moles diffuesd to the time taken for diffusion

The rate of diffusion is inversely proportional to the square root of its molar mass.
$$\displaystyle \dfrac {r_{O2}}{r_X}=  \dfrac {n_{O2}}{t_{O2}} \times \dfrac {t_{X}}{n_X} =\sqrt {\dfrac {M_X}{M_{O2}}}$$
$$\displaystyle n_{O2}=n_X$$
 $$\displaystyle    \dfrac {n_{X}}{ 18} \times \dfrac {45}{n_X} =\sqrt {\dfrac {M_X}{32}}$$

 $$\displaystyle   \dfrac {45}{ 18}  =\sqrt {\dfrac {M_X}{32}}$$
 $$\displaystyle    \dfrac {(45)^2}{ (18)^2}= \dfrac {M_X}{32}$$
The molecular mass of gas X is $$\displaystyle M_X = 32\times \dfrac {(45)^{2}}{(18)^{2}}$$  g/mol.

Solution

The formula for density is given below:
$$\displaystyle \text{Density}=\frac{n\times M}{a^3\times N_0}\displaystyle=\frac{2\times213}{(4.366\times10^{-8})^3\times6.02\times10^{23}}$$ $$=8.50$$ g cm$$^{-3}$$

SOLUTION

The correct order of decreasing ionic radius among the following anions would be I⁻,Se²⁻,Br−,O²⁻,F⁻ 

On moving down the group, the ionic radii increases as new shells of electrons are added. The radius of the isoelectronic species decreases with increasing charge.

Formul of sodium ferrocyanide Na4?[Fe(CN)6?] of suggest that it has four sodium atoms.

Number of Na atoms= Number of moles × number of atoms per molecule × Avogadro number

=2×4×6.023×10²³

=48×10²³