Solution:
Solution
$$ \Rightarrow R = 2\Omega $$
$$ \Rightarrow {V_{rms}} = 220V$$
$$ \Rightarrow {V_ \circ } = 220\sqrt 2 $$
$$\Rightarrow {X_L} = WL = 100\pi \times 0.7$$
$$ \Rightarrow 100\dfrac{{22}}{7} \times \dfrac{7}{{10}} = 220\Omega $$
$$\therefore z = 220\sqrt 3 $$
also $$\tan \phi = \dfrac{{{V_L}}}{R} = 1$$
$$\phi = {45^ \circ }$$
$$\therefore$$ wattless current$$ = {i_ \circ }\sin \phi $$
$$ = \dfrac{{220\sqrt 3 }}{{220\sqrt 2 }}\sin {45^ \circ }$$
$$ = \dfrac{1}{{\sqrt 2 }} = 0.7A$$
so we get $$0.7A$$