NSEP PHYSICS

DAILY PHYSICS TEST QUESTIONS

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1 Waves

A sonometre wire resonates with a given tuning forck forming standing waves with five antinodes between the two bridges when a mass of 9kg is suspended from the wire. When this mass is replaced by mass M, the wire resonates with the same positions of the bridges. Then find the value of square roof of M.

1) 5
2) 10
3) 25
4) none

Option 1

Option 2

Option 3 Solution:

Solution

The frequency of vibration of a string

$n=\dfrac{p}{2l}\sqrt{\dfrac{T}{m}}$

Also number of loops = Number of antinodes.

Hence with 5 antinodes and hanging mass of 9 kg. we have p=5 and T=9g

So,

$n_1=\dfrac{5}{2l}\sqrt{\dfrac{9g}{m}}$

With 3 antinodes and hanging mass M we have p=3 and T=Mg so,

$n_2=\dfrac{3}{2l}\sqrt{\dfrac{Mg}{m}}$

$\because n_1=n_2$

$\dfrac{5}{2l}\sqrt{\dfrac{9g}{m}}=\dfrac{3}{2l}\sqrt{\dfrac{Mg}{m}}$

Squaring both side we get

$25\times9=9\times M$

$M=25\ kg$

Option 4

The temperature of 100 g of water is to be raised from 24� C to 90� C by adding steam to it. Calculate the mass of the steam required for this purpose (latent heat of steam = 540 k Cal/kg)
1.10 g
2. 11 g
3. 12 g
4. 15 g

Option 1

Option 2

Option 3 Solution:

Option 4

3 Dual Nature of Matter and Radiation

Two radiations containing photons of energy twice and five times the work function of a metal one incident successively on the metal surface. The ratio of the maximum velocities of the emitted electrons in the two cases will be:

1).1 : 3
2).1 : 4
3).1 : 2
4).2 : 5

Option 1

Option 2

Option 3 Solution:

SOLUTION

$E - W_0 = \frac{ 1}{2} mv^2$

First case, $2 W_0 = W_0 = \frac{ 1}{2} mv_1^2$ ..(i)

Second case, $5 W_0 - W_0 = \frac{ 1}{2} mv_2^2$ ..(ii)

Therefore, from Eqs. (i) and (ii),

$\frac{ 2 W_0 - W_0 }{ 5 W_0 - W_0 } = \frac{ v_1^2 }{ v_2^2 }$ or $\frac{ v_1 }{ v_2 } = \frac{ 1}{2}$

Option 4

4 Laws of Motion

A cart on an air track is moving at 0.5 m/s when the air is suddenly turned off. The cart comes to rest after traveling 1 m. The experiment is repeated, but now the cart is moving at 1 m/s when the air is turned off. How far does the cart travel before coming to rest?

1) 1 m

2) Ö2 m

3) 2 m

4) 4 m

Option 1

Option 2

Option 3

Option 4 Solution:

Solution

1 / 2 mv² = f?x so if velocity is doubled then distance traveled will be four times as great.

5 Properties of Bulk Matter

When a capillary tube is dipped in a liquid, the liquid rises to a height h in the tube. The free liquid surface inside the tube is hemispherical in the shape. The tube is now pushed down so that the height of the tube outside the liquid is less than h

1) The liquid will come out of the tube like in a small fountain.
2) The liquid will ooze out of the tube slowly.
3) The liquid will fill the tube but not come out of its upper end
4) The free liquid surface inside the tube will not be hemispherical.

Option 1

Option 2

Option 3 Solution:

Solution

Consider a capillary tube of radius r immersed in a liquid of surface tension T and density $\rho$ . The height to which the liquid will rise in the capillary tube is given as $\dfrac{2Tcos\theta}{r\rho g}=\dfrac{2T}{R\rho g}$
or
$hR=\dfrac{2T}{\rho g}$ which is a constant.
Thus we get
$h_1R_1=h_2R_2$
When the tube is pushed down we are increasing the h, thereby reducing the radius R of the of the liquid meniscus. Thus as h increases, the level of the liquid becomes more and more flat but does not overflow

Option 4

6 Waves

The equation of a simple harmonic wave is given by y=6sin2π(2t−0.1x), where x and y are in mm and t is in seconds. The phase difference between two particles 2mm apart at any instant is

1) 18^o
2) 36^o
3) 54^o
4) 72^o

Option 1

Option 2

Option 3

Option 4 Solution:

SOLUTION

Given equation can be written as y=6sin(4πt−0.2πx)

∴ Phase ?=−0.2πx

⇒?₁=−0.2πx₁? and ?₂=−0.2πx₂?

∴ Phase difference Δ?=??₂−?₁??=?−0.2π(x₂?−x₁?)?

given (x₂?−x₁?)=2mm substituting in above equation we get Δ?=0.2×1800×2=720

7 Current Electricity

The electricity tariff in a town is Rs.3.00 per unit. Calculate the cost of running an 80W fan for 10h a day for the month of June.

1) Rs.12.00
2) Rs.52.00
3) Rs.72.00
4) Rs.92.00

Option 1

Option 2

Option 3 Solution:

Solution

Total time for which the fan is used =(10hours) × (30days)=300 hours.
Energy consumed =(80W)× (300 hours)
= 24,000Wh=24kWh.
But 1kWh = 1 unit.
Therefore, 24kWh = 24units
The cost of this power = 24 units × Rs.3 = Rs.72.00.

Option 4

8 Atoms and Nuclei

The wavelength of $H$ $_{\alpha}$ line in hydrogen spectrum was found to be $6563$ $\overset{o}{A}$ in the laboratory. If the wavelength of same line in the spectrum of a milky way is observed to be $6568$ $\overset{o}{A}$ , then recession velocity of milky way will be

1) 105 m/s
2) 1.05×10⁶m/s
3) 10.5×10⁶m/s
4) 0.105×10⁶m/s

Option 1

Option 2

Option 3 Solution:

Solution

$\nu = \displaystyle\frac{\triangle \lambda}{\lambda} \times c$

$= \dfrac{6586 - 6263}{6563} \times 3 \times 10^{8}$

$= 1.05$

$\times$ 10

$^{6}\ m / s$

Option 4

A diode can convert
1. ac to dc
2. dc to ac
3.ac to dc and vice versa
4.None of the above

Option 1 Solution:

A diode cannot convert dc into ac

Option 2

Option 3

Option 4

10 Physical world and measurement

In a screw gauge, the pitch of the screw is 0.5 mm and the number of circular scale divisions is 50, then the least count is __________ mm.

1) 0.05
2) 0.01
3) 0.5
4) 0.025

Option 1

Option 2 Solution:

Solution

Pitch P=0.5 mm
Number of divisions N=50
Least count L.C= N / P
?
= 0.5 mm/ 50
?
=0.01 mm

Option 3

Option 4

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