Solution:
Solution
In one complete oscillation a particle executing S.H.M travels a distance equal to $$4A$$ which is equivalent to $$2\pi$$ phase. In case question the greatest distance between $$P$$ and $$Q$$ is $$A$$. So, they should be separated by a phase$$=\cfrac { A }{ 4A } 2\pi =\cfrac { \pi }{ 2 } $$
Hence $$P$$ leads $$Q$$ by a phase difference of $$\cfrac { \pi }{ 2 } $$