Solution:
Solution
From Bohr's model of the atom:
$${ r }_{ n }=\dfrac { { n }^{ 2 }{ h }^{ 2 } }{ Z{ k }_{ e }{ e }^{ 2 }{ m }_{ e } } $$
where $${ r }_{ n }$$ is radius of the nth orbit
n is principal quantum number
h is reduced Plank's constant
Z is atomic number
$${ k }_{ e }$$ is coulomb's constant
e is electronic charge
$${ m }_{ e }$$ is the mass of electron
$${r}_{1} = 1 \times \dfrac{h^2}{1 \times k_e \times e^2\times m_e }= 5.03 \times 10^{-11} \Rightarrow \dfrac{h^2}{k_e \times e^2 \times m_e}= 5.03 \times 10^{-11} $$
$${ r }_{ n }=\dfrac { { { n }^{ 2 }h }^{ 2 } }{ { k }_{ e }{ e }^{ 2 }{ m }_{ e } } =20.12\times { 10 }^{ -11 }\\ \rightarrow { n }^{ 2 }=20.12\times { 10 }^{ -11 }\times \dfrac { { k }_{ e }{ e }^{ 2 }{ m }_{ e } }{ { h }^{ 2 } } \\ =20.12\times { 10 }^{ -11 }\times \dfrac { 1 }{ 5.03\times { 10 }^{ -11 } } \\ { n }^{ 2 }=4\\ \rightarrow n=2$$