Solution:
Solution
Given that temperature of the block is raised by $$\Delta T$$.
The heat gained by the block is, $$Q=ms\Delta T$$
Also energy stored in the capacitor is given by: $$E=\dfrac{1}{2}CV^2$$
$$\Rightarrow $$$$\dfrac{1}{2}CV^2=$$$$ms\Delta T$$
$$\Rightarrow V=\sqrt{\dfrac{2ms\Delta T}{C}}$$