Solution:
Solution
$$\begin{array}{l} At\, \, equilibrium,\, \, electric\, \, force\, \, on\, \, drop\, \, balances\, \, weight\, \, of\, \, drop. \\ qE=mg \\ q=\dfrac { { mg } }{ E } \\ q=\dfrac { { 9.9\times { { 10 }^{ -15 } } } }{ { 3\times { { 10 }^{ 4 } } } } =3.3\times { 10^{ -18 } }C \end{array}$$