Solution:
Solution
Given, $$\lambda =300m,C=2.4\times { 10 }^{ -6 }F$$
so, frequency, $$n=\cfrac { 3\times { 10 }^{ 8 } }{ 300 } ={ 10 }^{ 8 }Hz\quad $$
Resonance frequency, $$n=\cfrac { 1 }{ 2\pi \sqrt { LC } } $$
$$\sqrt { LC } =\cfrac { 1 }{ 2\pi n } $$
$$\Rightarrow LC=\cfrac { 1 }{ 4{ \pi }^{ 2 }{ n }^{ 2 } } \Rightarrow L=\cfrac { 1 }{ 4{ \pi }^{ 2 }{ n }^{ 2 }C } =\cfrac { 1 }{ 4{ \pi }^{ 2 }{ \left( { 10 }^{ 8 } \right) }^{ 2 }\times 2.4\times { 10 }^{ -6 } } ={ 10 }^{ -8 }H\quad $$