Solution:
Solution
In a uniform magnetic field, a charged particle is moving in a circle of radius R with constant speed v.
$$\therefore \displaystyle \frac{mv^2}{R} = Bqv$$ or $$\displaystyle R = \frac{mv}{Bq}$$ .......... (1)
Time period, $$\displaystyle T = \frac{2 \pi R}{v} = \frac{2 \pi m v}{B qv} = \frac{2 \pi m}{Bq} $$ ......... (2)
Time period T does not depend on both R and v because v is changed, R is also changed proportionately and for period, it is R/v that is taken.