Solution:
Solution
Electrostatic force =6 mg
Given
$$\dfrac {k(e)(e)}{x^2}=6(\dfrac {1}{6\times 10^{26}})\cdot g.$$
$$\dfrac {9\times 10^9\times (1\cdot 6\times 10^{-19})^2}{x^2}=\dfrac {10}{10^{26}}$$
$$x^2=10^{25}\times 9\times 10^9\times (1\cdot 6\times 10^{-19})^2$$
$$x^2=9\times 10^{34}\times (1\cdot 6\times 10^{-19})^2$$
$$x=3\times 10^{17}\times 1\cdot 6\times 10^{-19}$$
$$x=4\cdot 8\times 10^{-2}m$$
$$x=4.8cm$$