Solution:
Solution
Suppose we have n identical drops each having radius r, capacitance C, charge q and potential V. If these drops are combined to form a big drop of radius R, capacitance C', charge Q and potential V will become : Charge on big drop
Q=nq Capacitance of big drop
C′ = n1/3 C
Hence potential of big drop V′=Q / C′ =nq / n1/3C
= n 2/3C