Solution:
Solution
50 ml hard water = 6 mg CaCO3?
Assume the density of hard water to be 1 g/mol
50 ml hard water = 50 g or 0.050 kg
(because 1 kg = 1000 g)
Hence, 0.050 kg hard water = 6 mg CaCO3??
100 kg hard water =( 6mg / 0.050kg) ×100kg = 12000mg = 12 g CaCO3?
The molecular weights of Ca(OH)2? and CaCO3? are 74 g/mol and 100 g/mol respectively.
74 g Ca(OH)2?? = 100 g CaCO3?
12 g CaCO3 ? = (74 /100 )?×12
=8.9 g Ca(OH)2?