Solution:
Solution
Number of molecules of H2? in 1.36cm3 = (6.023×1023×1.36?) /22400 =3.66 × 1019
∴ Volume of H2? molecule =4.742 × 10−23
∴(4?/ 3)πr2 = 4.742×10−23
∴r = 2.246 x 10−8cm
Area of cross-section of H2? molecule =πr2 = 3.14×(2.246×10−8)2 =1.583×10−15cm2
Area of molecules adsorbed =(3.66×1019) × 1.583×10−15cm2= Area of adsorption of Cu powder = Specific area of Cu powder
∴ Specific area of adsorption of Cu =1.583×10−15 × 3.66×1019=579×102cm2
So, the value of y is 579.