Solution:
SOLUTION
CaO+H2C2O4→CaC2O4↓H2O
the NaOH would ne req to neutralize remaining oxalic acid
∴ initially no. of moles of CaO=0.56 /56 =0.01
no. of moles of H2C2O4=0.5×0.1=0.05mol
∴no. of moles of H2C2O4 remaining after reaction =(0.05−0.01)= 0.04 mol
H2C2O4(s)+2NaOH(aq)=Na2C2O4(aq)+2H2O(l)
∴0.04×2 mol NaOH will be required.(as oxide acid in aipetic)
∴ volume =moles / malarity = 0.08 / 0.2 = 400mL