Solution:
Solution
Consider a capillary tube of radius r immersed in a liquid of surface tension T and density $$\rho$$. The height to which the liquid will rise in the capillary tube is given as $$\dfrac{2Tcos\theta}{r\rho g}=\dfrac{2T}{R\rho g}$$
or
$$hR=\dfrac{2T}{\rho g}$$ which is a constant.
Thus we get
$$h_1R_1=h_2R_2$$
When the tube is pushed down we are increasing the h, thereby reducing the radius R of the of the liquid meniscus. Thus as h increases, the level of the liquid becomes more and more flat but does not overflow
