Solution:
Solution
Pressure exerted on the surface$$=P=\dfrac{F}{A}$$$$=\dfrac{\dfrac{dp}{dt}}{A}$$
Momentum $$p=\dfrac{E}{c}$$
where E is the energy of incident light, c is the speed of light.
Thus $$P=\dfrac{1}{c}(\dfrac{1}{A}\dfrac{dE}{dt})$$$$=\dfrac{Flux}{c}$$$$=\dfrac{18\times 10^{4}}{3\times 10^8}=6\times 10^{-4}N/m^2$$