Solution:
Solution
For pure inductive circuit, Current lag by $$\dfrac { \pi }{ 2 } \\ $$
inductive reactance $${ X }_{ L }=\omega L=2\pi fL\\ { X }_{ L }=2\times \dfrac { 22 }{ 7 } \times 0.7\times 50\\ { X }_{ L }=220$$
$$ Current \ through \ inductor \ i=\dfrac { V }{ { X }_{ L } } =\dfrac { 220 }{ 220 } =1Amps$$